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for (int i = 0; i < nPlayer; i++) { // Check for a tie. if (i != leadingPlayer && players[i]->Score == players[leadingPlayer]->Score) { return -1; } } return leadingPlayer; } // Implement a pass move in which a player throws back a certain // number of her tiles and draws new ones. // Return true if successful. bool Pass(List<Tile^>^ workingTiles) { if (bag->Count != 0) { int code; // Get the desired tiles to replace to // the bag from the user. Console::WriteLine("Enter tiles to throw back: "); do { code = Console::Read(); wchar_t character = safe_cast<wchar_t>(code); Letter letter = Letter::_; if (character == safe_cast<wchar_t>(Characters::NEWLINE)) { Console::ReadLine(); break; } if (character == '_') { letter = Letter::_; } else if (Char::IsLetter(character)) { if (Char::IsUpper(character)) { letter = safe_cast<Letter>(character - 'A' + 1); } else // character is a lowercase letter. { letter = safe_cast<Letter>(character - 'a' + 1); } }

At the very top of the e-mail message, you will see 1 Attachment or 2 Attachments, depending on the number of attachments.

5,030 2,779 1,852 1,389 1,111 926 794 695

If the document is a Microsoft Office document format, you will then be presented with the option to View or Edit with Documents to Go. For a quick view, without the option to edit or change the document, select View.

Ignore, for the moment, the last two columns, which are reporting the results with CPU costing enabled, and focus on the first three sets of costs. You will notice that the values for 9i and 10g don t quite agree with each other, but at least they are reasonably close to (serial cost / degree of parallelism). But the most obvious feature is that the cost in 8i never changes, no matter what the degree of parallelism. Essentially, 8i costs and optimizes your query for the best serial path, and then runs it in parallel. On the other hand, 9i assumes that it can execute a completely collision-free 100% parallel run, effectively optimizing for a set of data downsized by a factor of (degree of parallelism). Allowing for small rounding errors, the numbers from 10g suggest that it has introduced a parallel efficiency factor of 90% in the arithmetic. The actual figures suggest the following version-dependent formulae for a parallel tablescan:

// See if the letter is in the player's hand. Tile^ tile = gcnew Tile(letter); Tile^ tileToRemove = nullptr; bool tileFound = false; for each (Tile^ t in workingTiles) { if (t->LetterValue == tile->LetterValue) { tileToRemove = t; tileFound = true; break; } } if ( tileFound == true) { workingTiles->Remove( tileToRemove ); bag->Add(tile); } else // The letter was not found. { Console::WriteLine("You do not have enough {0}s to pass back.", letter); Console::WriteLine("Press any key to continue..."); Console::ReadLine(); return false; } } while (code != safe_cast<int>('\n')); // if bag->Count == 0

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8i 9i 10g Cost at degree N = serial cost Cost at degree N = ceil(serial cost / N ) Cost at degree N = ceil(serial cost / (0.9 * N))

If you get an error message such as Document Conversion Failed it is very likely that the attachment is not a format that is viewable by the BlackBerry Attachment Viewer. Check out the list of supported attachment types on page 250.

This leaves you with three issues to consider. First, 8i is not optimizing parallel queries properly. Second, as you upgrade, costs of parallel execution can change dramatically, and you may not be able to predict the side effects. Third, the arithmetic used by 9i assumes that there will be absolutely no interference between parallel execution slaves and that s not going to be very realistic in most cases. The change between 8i and 9i is controlled by parameter optimizer_percent_parallel (hidden from 9i onwards as _optimizer_percent_parallel). In 8i, the default value was zero in other words, calculate as serial. In 9i the default value is 101 which causes Oracle to perform its calculations on the basis of 100% parallelism. You can, in theory, set the parameter to any value between 0 and 101. If you do, then the optimizer does a straight-line interpolation between the serial cost (the Resc figure in a